this question is related to statistics and probability?

Question

A firm manufactures refrigerators at three plant locations A, B and C. For each location, the firm maintains a record of the refrigerators made at that plat, which require repair before expiration of warranty. Following is the summary of the information about repairs:

•Plant A produces 30% of all refrigerators and has a repair rate before warranty expirations, of 5%.

•Plant B produces 45% of all refrigerators and has a repair rate before warranty expiration, of 3%

•Plant C produces 25% of all refrigerators and has a repair rate before warranty expiration, of 7%.

If a refrigerator requires repair before warranty expiration what is the probability that it was manufactured at Plant B?

Answer 1

OK to work out that probability you need to do the probability of the refrigerator being made at Plant B AND it expiring before the warranty ends.
In probability AND means x so to work it out you do:
the probability of the refrigerator being made at Plant B x the probability of it expiring before the warranty ends.
This equals
45/100 (45%) x 3/100 (3%)
Which makes
0.0135 (Out of 1 - definite)
Or, in percentage (x 100) 1.35%

Answer 2

Think about this question using actual production numbers. If the firm manufactures 10 000 fridges in a year the numbers for each plant are:
A = 3000
B = 4500
C = 2500

And the number of fridges requiring warranty repair are the number of fridges multiplied by the percent requiring repair (shown below as a decimal).
A = 3000 X 0.05 = 150
B = 4500 X 0.03 = 135
C = 2500 X 0.07 = 175

The total number of fridges needing warranty repair is
150 + 135 + 175 = 460

The fraction from plant B is 135/460 = approx 29%

Answer 3

10%

Answer 4

with curling you can see maybe who wins the game based on if a team wins the first match or not