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Is it possible to find the size of each internal angle of an irregular polygon? If the answer is yes then how is this done?

2006-11-19 02:41:48 · 7 answers · asked by helen y 1 in Science & Mathematics Mathematics

7 answers

Measure them with an accurate measuring device.

2006-11-19 02:46:36 · answer #1 · answered by ? 6 · 0 0

You can determine the angles but only if there is sufficient additional information. For a triangle, if the lengths of all 3 sides are known, that is sufficient.

Next look at a four sided figure. Imagine it as four sticks pinned together at the corners. You can open and collapse the shape so the lengths of the sides alone is no longer enough. If one angle is fixed, then the whole shape is fixed. So you need all four sides and one angle. After that, all the other angles can be determined by using geometry where your divide the shape into two triangles and use the law of cosines and law of sines to figure the angles.

As you add additional sides, each side adds two unknowns, the length and angle of the side. If you assume you know all the lengths, then you need to know one more angle to fix the shape of the polygon.

In short, for an n sided ploygon, you need to know 2*n - 3 values. The values can be the side lengths or the angle but that is the minimum needed.

2006-11-19 03:06:38 · answer #2 · answered by Pretzels 5 · 0 0

Algebraically, it's only possible if some information about the angles is given.
For example, the measures of the six angles of a hexagon are consecutive odd integers. Find the measures.
You'd write an equation:
x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 360 (6-2) and solve it.

2006-11-19 02:50:52 · answer #3 · answered by hayharbr 7 · 0 0

measure it, but if you cany do that you can still MAYBE work it out.

you can find out how much they must add up to using the formula

(n-2) x 180 n is the number of sides

you will then have to use some of the other properties of the polygon or other internal angles if given.
you could also use the external angles. these will add up to 180 with the internal angle it is with
also all external angles add up to 360 in ANY polygon

hope this helps
if you have more info given in the problem post it agian and i will help more

2006-11-19 02:47:44 · answer #4 · answered by Anonymous · 0 0

because of the fact i substitute into too busy eating and getting stoned in college to take heed to such meaningless crap. yet I certainly have actual found out my lesson because of the fact an afternoon would not circulate by utilising while i'm no longer asked to locate the degree of each perspective in an peculiar polygon. regrettably, it extremely is how I lost my spouse an my ultimate pal, in an peculiar polygon twist of destiny back in 'ninety 4. If only i could have been able to calculate those angles somewhat faster......... I certainly have my regrets, beneficial. Who would not, yet who're you to choose me?

2016-11-25 19:34:20 · answer #5 · answered by Anonymous · 0 0

if its irregular,you'll just have to measure
it-the sides and angles won't be equal
so get out your ruler and protractor and
start measuring the lengths and angles,
break it into triangles and smooth out your
measuring errors

i hope that this helps

2006-11-19 04:01:21 · answer #6 · answered by Anonymous · 0 0

if u mean angle at center
=360/no. of sides
if u want angle b/w sides
=180(n-2)/n
where n is no. of sides

2006-11-19 02:50:37 · answer #7 · answered by Dupinder jeet kaur k 2 · 0 0

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