a)Explain how the disolution process of CaBr2 differs from that of glucose(C6H12O6)?
b)A 2.00M CaBr2 solution and a 2.00M glucose solution are both placed in a freezer whose temperature is -5C. which solution would NOT freeze? Kf=1.86C/M. WHY?
This is a bonus question for my chem class (8th grade) we are allowed to find the answer anywhere, then we have to (explain) present it to the class for bonus points. It could boost my grade to an A. PLEASE HELP if you can.
2006-11-19 02:30:06 · 1 answers · asked by mtta_girl 2 in Science & Mathematics ➔ Chemistry
The solute CaBr2 contains 3 ions, which are all separated when it dissolves in water.
Glucose, although it is a big molecule, is only one particle. Therefore CaBr2 provides three times the lowering of freezing point that glucose does
Both substances are freely soluble because the particles have a good attraction to water. But the solution of CaBr2 will not freeze at -5C because it has 6.00M of ions in it (3 x 2.0M).
2006-11-20 05:51:00 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋