x=5
2006-11-19 00:50:45
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answer #1
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answered by erotikos_stratiotis 4
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X=5
2006-11-19 09:11:34
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answer #2
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answered by jim j 1
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3(2x-1)=27
solve parentheses first
3(2x-1) multiply 3x2x and 3x-1
6x-3=27
add 3 to both sides
6x-3+3=27+3
6x=30
divide both sides by 6
x=5
2006-11-19 09:13:21
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answer #3
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answered by dr.xratedice 1
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3(2x-1)=27
Distribute the three to 2x and 1
6x-3=27
Get rid of the three in order to isolate the variable. Since it is being subtracted on the left, you will need to add it to the left and right. It cancels out on the left.
6x=30
Since six is being muliplied to x, you will need to divide it on both sides. The six cancels on the left, but when divided by 30, you are left with the answer.
x=5
2006-11-19 10:09:41
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answer #4
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answered by Kaylin 4
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2x-1=27/3
2x=9+1
x=10/2
x=5
2006-11-19 09:16:49
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answer #5
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answered by ????? 7
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2x-1=27/3
2x=9+1
x=10/2
x=5
2006-11-19 08:52:59
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answer #6
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answered by Monica J 2
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3(2x-1)=27
step1) 3(2x-1)=6x-3
step2)6x-3=27
step3)6x=30 .......27+3=30
step4)x=30/6=5
answer---------x=5
hope u hv understud the steps....
2006-11-19 10:18:48
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answer #7
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answered by disha 2
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3(2x-1)=27
6x-3=27
6x=30
x=5
2006-11-19 11:06:43
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answer #8
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answered by sushobhan 6
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3(2x-1)=27
2x-1=27/3
2x-1=9
2x=9+1
2x=10
x=10/2
x=5
2006-11-19 09:11:43
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answer #9
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answered by isis 3
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6x -3 = 27
6x = 30
x = 5
2006-11-19 08:52:13
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answer #10
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answered by Anonymous
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