You just add milk and thats it!! Hmm chocolate.........:)
2006-11-18 05:44:53 · 16 answers · asked by Siu02rk 3 in Food & Drink ➔ Cooking & Recipes
I know!!!!! Like, SOOOO delish :D
2006-11-18 05:55:24 · answer #1 · answered by ♥Bella♥ 3 · 1⤊ 0⤋
I know they re brilliant eh? I often have a bowl instead of dinner when I cant be bothered to cook. There is an own brand in France almost exactly the same as coco pops called choco crack! I bought them just for the name!!!!
2006-11-18 06:15:18 · answer #2 · answered by azteccamera 4 · 1⤊ 0⤋
Frosties or crunchy nut cornflakes for me with ice cold milk. Mmm supper time me thinks!
2006-11-18 10:18:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
no, a bowl of porridge is better for you. coco pops are full of sugar. much better snacks are peanut butter on toast, or some fruit.
2006-11-18 06:27:41 · answer #4 · answered by grumpcookie 6 · 0⤊ 0⤋
Erm..No..i think that angel delight is definitely tastier than manky coco-pops..and its quick
2006-11-18 06:03:03 · answer #5 · answered by matthew 1 · 0⤊ 0⤋
do you've lunch meat and cheese?? make a ham and cheese sandwich and grill it and make some soup. you may want to reduce up potatoes and upload them for your soup. you may by no potential flow incorrect with breakfast for dinner both so perhaps make french toast or waffles. our hash browns and tacky eggs. darn, now im hungry....
2016-11-29 06:17:09 · answer #6 · answered by ? 4 · 0⤊ 0⤋
lol! I've been eating coco pops for years now. They don't seem as nice...not as chocolatey.
2006-11-18 05:47:59 · answer #7 · answered by jewl 32 2 · 0⤊ 0⤋
i think so! whenever i'm hungry, and there is nothing to eat, i only eat coco-pops.
2006-11-19 00:49:48 · answer #8 · answered by Jia 2 · 0⤊ 0⤋
butterscotch flavour angel delight deelicious
2006-11-19 01:48:08 · answer #9 · answered by cozz 2 · 0⤊ 0⤋
No not at all..
Its got to be Cornflakes, or popcorn
2006-11-18 05:57:02 · answer #10 · answered by Baps . 7 · 0⤊ 0⤋
crunchy nut cornflakes
2006-11-18 05:47:02 · answer #11 · answered by cereal killer 5 · 2⤊ 0⤋