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what is the appropriate interpolation degree of f(x)=ln(x) ?
for x=2.35 to 2.39 with h=0.01

and how can i find the appropriate degree of interpolation ???

2006-11-16 21:30:33 · 2 answers · asked by Anonymous in Science & Mathematics Engineering

2 answers

get the answer from below web

2006-11-16 21:35:04 · answer #1 · answered by CK 4 · 1 0

You have only 2 "known" points, so your degree is 1:
p(x) = 0.85441(x - 2.39)/(2.35 - 2.39) + 0.8713(x - 2.35)/(2.39 - 2.35)
p(x) = 0.8544(x - 2.39)/-0.04 + 0.8713(x - 2.35)/0.04
p(x) = -21.36(x - 2.39) + 21.7823(x - 2.35)
p(x) = -21.36x + 51.0513 + 21.7823x - 51.1888
p(x) = 0.4223x - 0.1375,
with an average error of 0.055%

2006-11-17 07:01:26 · answer #2 · answered by Helmut 7 · 0 0

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