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Defination of temperature compensation of capacitor

2006-11-16 15:22:55 · 4 answers · asked by sateesh nalawade 1 in Science & Mathematics Engineering

4 answers

A way to make sure the capacitance doesn't change with temperature. This can be done by selecting a suitable dialectric material to make the capacitor, as with "NP0" capacitors (NP0 means "negative-positive zero," meaning no - or + temp. coefficient). One could also design a circuit to compensate for capacitance changes due to temp, such as, using a thermistor and transistor to provide a voltage that varies with temperature, and applying it to a vari-cap placed in parallel with the capacitor.

2006-11-16 16:00:33 · answer #1 · answered by pack_rat2 3 · 0 0

CAPACITORS are made of two dissimilar metal plates separated by an insulator (dielectric). The value (amount of charge) of the capacitor is determined by 1. size of plates.
2. type of material used 3. thickness of the dielectric. If you want to vary the value you can alter the surface (as in an old radio tuner) or can vary the thickness of the dielectric (as in silicone filled transmitters). These variable type capacitors are sensitive to temp changes, All this said, it just means that without any electrical changes in a circuit, fluctuations can occur due to ambient temp changes. The ambient temp change will alter the distance between the plates and thus the output value, without and change in circuit function..
A compensator detects the ambient temp and moves the plates or the charge back to where they belong.

2006-11-16 16:19:56 · answer #2 · answered by HeyDude 3 · 0 0

Temperature pressure compensation is a process to adjust the measure of a fluid to bring it to some standard conditions for comparison with other measurements. It is very common in the measurement of gases but can also apply to liquids since they are also subject to changes in volume with temperature and sometimes pressure.

2016-05-21 21:58:36 · answer #3 · answered by Anonymous · 0 0

If the inductace of a circuit is given as r-jc+jL, then termperatures can reduce it to r'-jc'+jl'. Usually it is compensated by providing a shunt resistor at the output before the load whose value can be calculated from above.

2006-11-17 05:06:49 · answer #4 · answered by Mathew C 5 · 0 1

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