it could be:
lander
picah
keiko
toshi
grim-lock
saphhire ~ i miss this old dog of mine, she was a dachshund too.. very gentle very loving.. never did she ever get mad at me or bite me and my loved ones.. experts say that the attitued of your dog is also besed on your dogs name.. because your dogs name is some kind of a symbol of something.. i have so many good dogs.. and sapphire is the best.. i miss her.. i miss her eyes.. she really is a very great dog.. 2 years have passed and im still very depressed...
goodluck in choosing a name for your dog. :)
2006-11-16 00:01:28
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answer #1
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answered by mini 1
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Gordon's is a type of gin - so you could continue the theme & call your new little guy Beefeater, Boodle, Bombadier or Gilbey.
Gordon & Gilbey sound quite good together
And Bombadier could be considered on a similar theme to Gunner.
Or you could always call the little one Tonic or Martini.
I think my favourite might be Boodle as it can be abbreviated to Boo.
There's more gin types/brands mentioned in Wikipedia:
2006-11-16 02:37:12
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answer #2
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answered by Solow 6
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Decker is better than gunner
2006-11-16 11:05:24
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answer #3
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answered by Kirks Folley 5
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Maverick
2006-11-16 00:00:03
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answer #4
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answered by Anonymous
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Sam, why I have no idea its just the first name that popped into my head. Or you could really trip people out and call him kitty
or how about oscar as in oscar mayer wieners . hes a wiener dog right.
2006-11-16 00:05:17
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answer #5
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answered by hersheynrey 7
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Storm, Wolfie, foxy, Worf, Bob, Ben
2006-11-15 23:58:57
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answer #6
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answered by ? 6
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For a boy puppy I like
Rumor
and
Romeo
Have fun with your new puppy!
2006-11-16 04:00:25
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answer #7
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answered by ♥Jade April♥ 4
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Fleaba
2006-11-15 23:54:22
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answer #8
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answered by samssculptures 5
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Your choices are nice.But I want to give you three more.Maybe Sharo,Spoko or...Puncky?:)
(By the way Decker is better then Gunner.The name of your other dog is already have G in it.)
2006-11-16 00:13:27
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answer #9
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answered by eli 2
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I really love Decker! It's so perfect!
2006-11-15 23:55:12
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answer #10
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answered by Anonymous
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