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I tried farting in my air filter to see if I can smell it on the other end. It does a really good job at keeping the smell out. Therefore, I was wondering what would be threshold in terms of the number of persons farting in the filter at once before you begin to smell it on the other end?

2006-11-15 08:29:37 · 9 answers · asked by Edwin Q 1 in Health Other - Health

9 answers

By my calculations and assuming that the farts have an average volume of 27 cu.in. and an average density of 1.0235 that of air (it's the .0235 that kills), I would approximate that the number would be in the range of 1435 - 2013 rippers. Now, of course, this is assuming that the gaseous subject stands at least a foot from the filter intake so that no "blowouts" occur. Other factors that I have not considered are: 1) the number of onions consumed 2) no introduction of corned beef and cabbage 3) no naked hineys (must be wearing 501 jeans) 4) no air sprays allowed to mask the overwhelming stench.
Good luck on proving my theory.

2006-11-15 08:54:36 · answer #1 · answered by Doug R 5 · 1 0

I don't think it's the volume, I think it's the particle size that the filter is blocking. Find a smaller person and have them try their flatulence to see if it gets through.

2006-11-15 16:38:03 · answer #2 · answered by shake_um 5 · 0 0

That depends on how many beef and bean barritos you can safely digest in a given time frame.
lmao !

2006-11-15 16:39:13 · answer #3 · answered by S.A.M. Gunner 7212 6 · 0 0

it depends on your age

teen - 8 - 12
adult - 9 - 15

2006-11-15 16:37:28 · answer #4 · answered by Anonymous · 0 0

Thats easy....5.

2006-11-15 16:31:46 · answer #5 · answered by kellythemayor 1 · 0 0

What? I can't believe you actually find time to do silly stuff like that.

2006-11-15 16:32:18 · answer #6 · answered by RACQUEL 7 · 0 1

quite a lot

2006-11-15 16:31:11 · answer #7 · answered by dm 2 · 0 0

You're bored, aren't you?

2006-11-15 16:32:55 · answer #8 · answered by greylady 6 · 0 1

676,009,786,988,123,453

2006-11-15 16:37:02 · answer #9 · answered by Anonymous · 0 0

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