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I need to convert a load of 340volts dc at 250 watts
to either 12volts dc at 250 watts
or 240volts at 250 watts

2006-11-14 19:22:16 · 8 answers · asked by Navyant 2 in Science & Mathematics Engineering

sorry about the confusion, I have a monitored 340v-250watt power supply that uses a current monitoring wattage on a feedback loop to detect if a globe is working or not. the present globe works on the above rating, I want to replace it with a globe of 240v, 250w.(all dc not ac) so I need to drop 100v and little (minimal) wattage loss.

2006-11-14 20:40:14 · update #1

8 answers

Not sure what you are trying to do but it kind of sounds like you are attempting to replace an arc-discharge light with an incandescent.

They have fundamentally different drive requirements. The arc-discharge has a negative resistance and it will not operate without a ballast designed specifically for that lamp. Such ballasts sometimes include active power-monitoring. The lamp and the ballast need to be paired with each other. Using a lamp and ballast not designed to work together will result in one of: won't work at all; will have very short life; will have unstable operation.

The incandescent lamp has a resistance that changes dramatically as the filament heats up and it is therefore self-ballasting. It works best when operated from an approximately constant-voltage source, not a constant-power source.

2006-11-15 04:41:53 · answer #1 · answered by AnswerMan 4 · 0 0

Voltage score itself isn't sufficient to make sure a circuit. you may point out what's your Load . what it going to force. VA score is often comparable for widely used and secondary. you may advance the voltage and cutting-edge will come down for the comparable VA score. because of the fact your source is low voltage DC it could have Very severe cutting-edge fro the comparable VA score. assume you have 1000VA load on the severe voltage factor say 1000 Volts. it has to deal purely 1A load. yet on the widely used source whether this is 10V it has to handle 100A load. i do no longer factor any 6V or 10V source can cope with thins cutting-edge. So be particular what you desire. what's your load on secondary and as a outcome you may desire to %. up the acceptable circuit. no longer that any factor will artwork. there are particular purposes for each style of circuit.

2016-12-17 10:20:44 · answer #2 · answered by ? 4 · 0 0

Although the question is a bit unclear, I would have to venture a guess that you are trying to find the current in each of these loads so that you have your 250 watts of power being dissipated. So, in each case, you would use the equation Power=(volts)(current), and solve for the current you would need to have the correct combination of power and voltage.

2006-11-14 19:35:58 · answer #3 · answered by tbirdwrestler 2 · 0 0

U need a dc - dc transformer voltage xfmr, it would basically keep ur power same while increase the ampacity. And your voltage will be at the desired lower setting.

2006-11-14 20:16:58 · answer #4 · answered by Sid Has 3 · 0 0

Assuming you know what you're talking about, you need a switcher. It converts DC to AC, transforms the voltage, then converts back to DC.

2006-11-14 20:11:38 · answer #5 · answered by Anonymous · 0 0

Your initial question is clear.
Your comment question is messing it up totally!
"A load of 340V/250W": you don't convert a "load".
What is your SOURCE of power (the thing that supplies the power, such as a battery, the mains)?
What is your LOAD (the thing that receives the power, such as a motor)?
Explain.

2006-11-14 19:27:07 · answer #6 · answered by just "JR" 7 · 0 0

To reduce dc voltage you would use risistors. a dc to dc transformer may work better for that hi a voltage drop.

2006-11-14 20:08:28 · answer #7 · answered by Robert F 7 · 0 0

try a different transistor

2006-11-14 19:30:58 · answer #8 · answered by The Truth 2.0 5 · 0 1

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