2006-11-13 08:32:49 · 5 answers · asked by Cesare F 1 in Science & Mathematics ➔ Engineering
It all depends on how much current will be drawn.
2006-11-13 08:51:12 · answer #1 · answered by pack_rat2 3 · 0⤊ 0⤋
Find a 16 gauge with a thin insulation for the winding. Like that for an electric motot, the dipped polymer type rather than thick plastic like honme wiring. More windings mean more gauss in the magnet. THicker wire and insulation means less windings.
2006-11-13 08:41:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i suggest a 14 gauge wire as a 16 gauge wire may not work as well as the the 14 gauge.
2006-11-13 08:37:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The power of the electromagnet is dependent on the magnetic saturation level of the magnet material, and the number of ampere-turns used to "boost" the magnetic field.
If you're looking to have a high-turn, low current magnet: use a wire of 812 CM (approximately AWG 20). This copper wire will have a resistance of 10.1 ohms/1000 ft and an allowable ampacity of 1.5 amperes.
For a low-turn, high-current magnet: use AWG 6 (0.395 ohms/1000 ft, ampacity of 37 amperes).
If you're really trying to stretch the envelope, you might even consider using AWG 0 (0.0983 ohm/1000 ft, 150 amperes).
Partly, it depends on the mean length of turn for your magnet winding ...
2006-11-13 09:31:24 · answer #4 · answered by CanTexan 6 · 0⤊ 0⤋
14 - 16 gauge wire will work fine.
2006-11-13 08:34:44 · answer #5 · answered by fr2fish 3 · 0⤊ 0⤋