(4/5+2/3)-(1/5)^2 is what?

0 ⤊

(4/5+2/3)-(1/5)^2 is what?

2006-11-09 10:44:45 · 3 answers · asked by ls1boi 1 in Education & Reference ➔ Quotations

3 answers

Answer: 1.46r
* r=recurring.

Solution:

(4/5+2/3)-(1/5)^2

4/5=0.8
2/3=0.66r
1/5=0.2

(0.8+0.66r)-(0.2)^2

0.2*0.2=0.04

(0.8+0.66r)-(0.04)

=(1.46r)-(0.04)

1.46r-0.04=1.426r

Edited: I read 2/3 as 3/2. I have changed the solution to correct my reading mistake.

2006-11-09 10:49:45 · answer #1 · answered by Dravos 2 · 0⤊ 0⤋

4/5+2/3=22/15.22/15-1/5=19/15.I don't know what ^ means so I can't finish the problem.

2006-11-09 18:54:35 · answer #2 · answered by debralizjr 4 · 0⤊ 0⤋

1.43

2006-11-09 19:07:16 · answer #3 · answered by trackstarr59 3 · 0⤊ 0⤋