i was testing some wire to see it's resistance and i want a way to see how to get it's wattage rating
(there has to be a way to do this)
2006-11-09 02:41:35 · 7 answers · asked by macgyver 1 in Science & Mathematics ➔ Engineering
It depends on the applied voltage. Divide the voltage by the resistance which gives you the amperage. Now multiply the amperage with the voltage, and that is your wattage.
W = V²/R
This is straight forward for DC; with AC things become a little more difficult, as because of the fluctuation of the voltage, the average is only .707 of the nominal voltage.
2006-11-09 02:44:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
No, there isn't.
The higher the resistance, more voltage drop, thus more heat being generated. Depending on the materials used for insulation, the maximum allowable current will vary. Also, depending on applications, maximum allowable voltage drop will be different.
For a given current limit, though, the wattage it can pass through the wire will rise depending on the voltage applied. The limit to this is an insulation material.
2006-11-09 02:51:01 · answer #2 · answered by tkquestion 7 · 0⤊ 2⤋
Wattage is the quantity of potential Its calculated by using fact the volts (elecrical rigidity) x the ampherage (the electrical powered bypass). thse at the same time supply you the quantity of potential for occasion a one hundred twenty volt mild bulb using a million amphere = one hundred twenty Watt bulb Your electric powered business enterprise rates you for electricity by potential of the Kilowatt-hour - consequently potential at 1000 W increments consistently used for one hour The greater wattage (you fan) the greater potential it consumes.. looking on layout, and so on and so on...the greater wattage the greater blow on your fan good success
2016-12-28 17:02:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Volts x amps = watts
V = Current x Resistance
so watts = current^2 x R
2006-11-09 02:45:47 · answer #4 · answered by davidosterberg1 6 · 1⤊ 0⤋
The ampacity (current capacity) of an electric cable is limited by the cable's capacity to dissipate thermal power. The ampacity of a cable is equal to the cable’s thermal power rating per unit length divided by its resistance per unit length.
2006-11-09 05:55:51 · answer #5 · answered by Deep Thought 5 · 0⤊ 0⤋
P = V * R (1)
V = R * I (2)
P = I * R^2 (3)
If you know the applied voltage use eq 1. If you know the current use eq. 3.
2006-11-09 02:51:24 · answer #6 · answered by Dr. J. 6 · 0⤊ 1⤋
Power (watts)=current x energy (volts)
2006-11-09 02:50:50 · answer #7 · answered by Eric 3 · 0⤊ 1⤋