The D70s was always a good deal but since the announcement of the D80 Nikon slashed the price of the D70s, making it GREAT value for money.
If you're on a limited budget, spend the $370 price difference on more or better lenses. (6 mega-pixels is plenty for an 8x10 inch print.)
The biggest attractions of the D80 are the jump to 10 mega-pixels and the larger viewfinder. Both of these are welcome improvements, and the $1000 price tag is justified - but only if you can also afford good lenses to take advantage of those 10 mega-pixels.
2006-11-07 10:40:58
·
answer #1
·
answered by OMG, I ♥ PONIES!!1 7
·
1⤊
0⤋
I vote with everyone here and choose OMG as the best answer. Just adding some support to everyone's information instead of writing my own answer. Personally, I think I'd lust after the D80, even if I saved a load of money on a D70s, though.
The D200 is a bit "better" than the D80, but I own a D70s and a D200 and I can tell you I rarely touch the D70s. It lives in my office, dedicated to macro work.
2006-11-08 16:00:49
·
answer #2
·
answered by Picture Taker 7
·
0⤊
0⤋
D80 has a better image sensor, LCD and viewfinder and it takes SD memory cards, not CF, also it's a little smaller than the D70 , but Higher in price,
Means if you don't care bout the larger LCD , and if you're always using a Max of 6 M-Pixels then go with the D70s with a better lens like the Nikon AF 18-200mm
2006-11-07 10:36:15
·
answer #3
·
answered by Hope 1
·
0⤊
0⤋
Supposedly the D80's electronics are better in every respect than the D70. I live in Australia and they cost the same here.
So I have just ordered the D80 (last one was a D50 - love it!)
2006-11-07 14:45:04
·
answer #4
·
answered by teef_au 6
·
0⤊
0⤋
The two main advantages of the D80 vs. the D70s are a bigger viewfinder and an extra 4MP. For me, those two improvements alone justify the price difference. On the other hand, if your budget doesn't allow for the D80 AND the lens(es) you want, it's better to economize on the body.
2016-05-22 08:41:57
·
answer #5
·
answered by Kimberly 4
·
0⤊
0⤋