2006-11-07 01:16:13 · 20 answers · asked by The False Prophet 2 in Society & Culture ➔ Religion & Spirituality
I agree with you 110%
2006-11-07 01:17:26 · answer #1 · answered by blackratsnake 5 · 0⤊ 1⤋
Before Internet chit-chat LOL stood for Little Old Ladies. The abbreviation now meaning laughing out loud can be an ice-breaker to let a recipient know there is no intended malice or hard thought coming their way.
2006-11-07 01:29:51 · answer #2 · answered by Guitarpicker 7 · 2⤊ 0⤋
lol = "lots of laughs" or" laugh out loud"
......it is computer slang used to indicate when the writer has found something amusing or when the writer wishes to convey that he/she is joking.
so it isn't dumb, just a modern form of computer short hand. There are many other computer slang abbreviations which are also used.
2006-11-07 01:23:11 · answer #3 · answered by Anonymous · 1⤊ 0⤋
It's just short for Laugh Out Loud. What's the big deal?
2006-11-07 01:19:42 · answer #4 · answered by Anonymous · 1⤊ 0⤋
I've been using the internet for 6 years and I've never said it yet. I just prefer to express myself in plain language.
2006-11-07 01:18:49 · answer #5 · answered by Anonymous · 2⤊ 0⤋
I will not even date a women that's says LOL and then they wonder why LOL @ THEM
2015-09-10 11:09:40 · answer #6 · answered by Anonymous · 0⤊ 0⤋
You've got some snarky answers here.
Strange isn't it how people in this category are disrespectful.
One would think ESPECIALLY in this category would one find politeness and respect!
Don't cower at the ridiculers ....ask your questions and make your statements!
2006-11-07 01:24:03 · answer #7 · answered by Uncle Thesis 7 · 2⤊ 0⤋
If your to old to understand the computer language, maybe you shouldn't be using one?? LOL
Do you even know what it means??
Laugh Out Load
2006-11-07 01:20:01 · answer #8 · answered by Stormy 2 · 1⤊ 0⤋
Lol
2006-11-07 01:17:59 · answer #9 · answered by Twilight_dreaming 4 · 1⤊ 1⤋
None of your time said this? im not sure what you are talking about?
2006-11-07 01:17:28 · answer #10 · answered by K 5 · 1⤊ 1⤋