A bag contains equal numbers of blue and red marbles. If two of them are drawn from the bag at random, the odds against their both being red are four to one.
Instead of drawing these two marbles, however, I draw(at random) some of the marbles from the bag, and transfer them to a second bag, which I will call Bag 2. Now one marble is drawn at random from Bag 1 and a second from Bag 2.
What are the odds against their both being blue?
2006-11-06 19:17:54 · 3 answers · asked by enigma 1 in Entertainment & Music ➔ Jokes & Riddles
Still four to one.
Regardless of which bag you draw marbles from the odds are still 50/50 that it will be either red or blue.
2006-11-06 19:25:06 · answer #1 · answered by Anonymous · 1⤊ 0⤋
i shouldn't even answer cuz rooksie is 100% correct, but i verify that answer.
2006-11-06 19:33:05 · answer #2 · answered by Anonymous · 1⤊ 0⤋
this riddle is more like my math question in probability...
2006-11-06 19:40:01 · answer #3 · answered by I need a vacation! 4 · 0⤊ 0⤋