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its for science for technicians so will anyone help me i am majorlly stuck

2006-11-06 07:47:13 · 3 answers · asked by morgan a 1 in Science & Mathematics Engineering

3 answers

I will try.
Not because it is difficult to understand but difficult to describe. Let us take a three member truss.

A truss must be in equilibrium otherwise it will fall into its three component pieces. Lets assume it is for a roof

From its apex to the two walls its load will come from the tiles, and for these the angles and weights are calculated to establish what portion of it goes to which joint.
The two portions at the top are examined together to make sure their loads will be stable against each other.
The portions at the bottom are being supported by two walls but they have two components each. One wants to rest on the wall while the other is trying to move away from the wall.
To keep this from happening we have to introduce our third truss member and make sure it can take the tension required of it.
Now we know all the points we can show the summation of all the loads and ascertain if they are in compression or tension.
When we have selected or designed each of our truss members we can fix them to keep the whole assembly stable.
Now the truss it in equilibrium.
Try it with large match sticks and think of what you are reading.
It might help.

2006-11-07 22:32:28 · answer #1 · answered by Anonymous · 0 0

Here's an example.... A pendulum is suspended from an axle by a cord. To keep it simple, lets say that the pendulum is at rest and the mass of the cord is negligible.....

Now draw a circle to represent the pendulum weight. The force acting downwards (F) is the mass of the weight multiplied by g ( the acceleration due to gravity). This is balanced by the tension in the cord (T).

So T= F =mg

Represent this balance of forces on the weight by drawing an arrow pointing vertically down from the weight. Label this arrow F. Finally draw another arrow vertically up from the weight and label this T.

Follow a similar procedure to balance the forces on the axle. i.e. draw a circle to represent the axle. Only this time the force pointing down is the Tension in the cord (T) and the force up is the reaction force at the axle (Fr).

2006-11-06 09:30:20 · answer #2 · answered by spoon_bender001 2 · 0 0

Forces are vectors. Draw them tip to tail, and they should add up to the resultant.

2006-11-06 07:51:08 · answer #3 · answered by daedgewood 4 · 0 0

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