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5 answers

Do a search on the net for the artist's name and include "prices" or "value." Finding a contemporary artist's agent would be ideal. Doing a search on eBay may find comparable pieces that you can compare.

Your question is very broad. If you are searching for an unknown artist, then finding a dealer who may have heard of him/her would be the answer. If you live in a large city, there are art dealers / galleries who may be able to help you. In Los Angeles, they are legion.

If you can access large auction houses like Butterfield and Bonham, they may help with collected artists' works.

good luck

2006-11-05 13:06:40 · answer #1 · answered by vertically challenged 3 · 0 0

These sites seem to have a lot of info: www.absolutearts.com and www.wwar.com.

You can enter an artist name, medium, location, etc. and see what comes up. If the artist is dead some gallery contact might come up. Those galleries can give you more info on the worth of pieces, the time frame, medium, etc. The might be able to put you in touch with buyers (if you are interested). Value of art depends on the condition and if it's an original and when in the artist's career it was produced.

2006-11-05 22:57:25 · answer #2 · answered by Anonymous · 0 0

If you live in a large or medium-szied city, an auction house that handles paintings and prins, can evaluate the paintings/prints for you.

Before you leave your paintings and prints with an auction house, go to the Better Business Bureau website (bbb.org) to make sure ther are no complaints about the auction house.

2006-11-05 21:16:38 · answer #3 · answered by newyorkgal71 7 · 0 0

The true value of anything is what someone will pay for it.
So, try to sell it.

If that's not what you want, take it to a large art gallery and see if they can find an "Art Appraiser" for you. They may need to hold it or send it to the Appraiser and it may cost some bucks. Tell them you need the value for insurance reasons.

2006-11-06 05:17:38 · answer #4 · answered by James H 3 · 0 0

try google

2006-11-05 21:06:52 · answer #5 · answered by Anonymous · 0 0

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