How much pressure id required to lift water in a cylindrical pipeline of 100 ft hight and 1 ft diameter?

Question

can anyone tell me how much air pressure in psi is required to lift water by 100 ft in a cylindrical pipe of 1 feet diameter and 100 ft hight using 1 inch diameter airline. can anyone give me the formula.

can anyone tell me how much air pressure in psi is required to lift water by 100 ft in a cylindrical pipe of 1 feet diameter and 100 ft hight using 12 inch diameter airline. can anyone give me the formula.

Could u please include the answer too and mention it clearly

Answer 1

The only way I can see this being done is to have a piston or other way to separate the water and air; otherwise, the air will simply bubble up through the water.

Assuming there is a piston or other separation device and the water will overflow at the top, the initial pressure needed to begin the displacement of the water is the height of the water in inches times its density in pounds per cubic inch. Taking the density of water as 62.4 pounds per cubic foot and converting to pounds per cubic inch the density becomes .036111. The height is of course 100 ft time 12 inches per foot or 1200 inches. This yields an initial pressure of 1200 time .036111 or 43.33 psi. As the piston moves upward, the required pressure will decrease directly in proportion to its height or .4333 psi per 12 inches of rise.

Answer 2

Well, the diameter is not really relevant on the pressure required.

100 ft of water = 100 (144/62.4) = psi

(144 in^2/ft^2) converts ft^2 to in^2

density of water about 62.4 Lbs/Ft^3

If you're really going to do this you're going to run into a problem. the air is going to bubble through the water and escape out the top.

Answer 3

Pressure = height x density. Diameter is not part of the equation. !00 ft x 62.4 lb/CF = 6240 lb/SF. Covert to psi by dividing by 144 sq.in/SF. You get 43.33 psi

Answer 4

It look that your question replaced into decrease off. All we are able to make certain is: "the commencing place for a cylindrical water tank is a cylinder 24 feet in diameter and four feet severe. what share cubic feet o?" Is there greater to it?

Answer 5

p=specific gravity*head
p=62.427 962 178*0.304 8 lb/cu foot for water
(1 000 kilogram/cubic meter = 62.427 962 178 pound/cubic foot,
1 feet [international, U.S.] = 0.304 8 meter)
p=.078*.3048 lb/cu foot for air
pressure=force/area
velocity=sqrt(2*g*h)
volume flow rate=area*velocity

Air pressure should exceed the water pressure to lift the water column.

The efficiency of the system reaches 22% when the ratio of water to air flow rate equals 2.15 and decreases thereafter.
CALCULATE THE WEIGHT OF THE WATER TO BE DISPLACED AND AT WHAT RATE.
PL. VISIT:
http://www.aquaticeco.com/index.cfm/fuseaction/popup.techTalkDetail/ttid/97
http://www.akca.org/library/liftair.htm

Answer 6

Find the volume of water (100*3.14 cubic feet), find how much that weighs by multiplying by the density in lb/cuft. That how many pounds of force you need, so divide by 3.14 square inches to get PSI.