power factor onboard marine emgineering ships
2006-11-03 00:14:07 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
In a purely resistive circuit, the power factor (PF) is 1 and you *can't* adjust it.
And, since this is the 3'rd time you've asked the question and gotten the same answer from one other person and myself, do you even know what 'Power Factor' *is*?
Doug
2006-11-03 00:17:08 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
There is nothing to adjust in a purely resistive circuit. The power factor is 100%. Any other power factor is caused by a capacitive or inductive (or a combination thereof ) load.
2006-11-03 15:38:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The power factor in a purely resistive load is 1 (unity). The only way it can change is the introduction of capacitive or inductive loads. Go to www.wikipedia.org and search for Power Factor for a detailed explanation.
2006-11-06 01:51:20 · answer #3 · answered by Paul 1 · 0⤊ 0⤋
Power factor is 1 if the circuit is purely resistive. It only varies if you add some capacitance or inductance into the circuit.
2006-11-03 00:23:14 · answer #4 · answered by Roger B 3 · 0⤊ 0⤋