2006-11-02 07:24:54 · 6 answers · asked by Blue_Falcon 2 in Science & Mathematics ➔ Engineering
hook the wires backwards
2006-11-02 16:12:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
This one's not so easy. If you use the +24 VDC supply from your other question and connect a 7905 and a 7812 to its output you can make the -5 VDC anc +12 VDC you are looking for. Beware though, the new "ground" for this circuit will be at +5 V relative to real ground.
2006-11-02 15:50:39 · answer #2 · answered by frieburger 3 · 0⤊ 0⤋
Place a resistor on the circuit, or similar load such as a light.
Voltage drops over the course of a circuit. It may start at the negative terminal as 12V, but as the circuit encounters loads, it drops until it reaches the positive terminal where it is 0V. Voltage is defined as the potential difference between the positive and negative terminals.
If no load is encountered, the circuit is shorted.
2006-11-02 16:40:41 · answer #3 · answered by warmspirited 3 · 0⤊ 1⤋
7905 Linear regulators have the least parts count but they are very inefficient. If you want efficiency, use a buck-boost converter.
Designs for these are available everywhere in the internet.
2006-11-03 00:26:18 · answer #4 · answered by capuxx 1 · 0⤊ 0⤋
All you need is a voltage rectifier and this thing that they use in car alternators called a diode trio.
2006-11-02 15:59:33 · answer #5 · answered by kinetic_91 1 · 0⤊ 1⤋
you can't... you need to get a negative supply
first answer, that's not -5v if it has a hot ground of +5v
second answer, you can't rectify DC voltage, it's already rectified.
2006-11-02 16:00:00 · answer #6 · answered by Anonymous · 0⤊ 0⤋