2006-10-31 15:57:56 · 7 answers · asked by SERGEY K 1 in Science & Mathematics ➔ Engineering
Poor boy, he doesn;t know what "you're looking for" or how many amps "you're pulling" which is what "you are" looking for.
2006-10-31 16:20:46 · answer #1 · answered by ? 6 · 0⤊ 0⤋
Volts X Amps = Watts
2006-10-31 16:09:17 · answer #2 · answered by szydkids 5 · 0⤊ 0⤋
I'm not sure I know if this is what your looking for but; watts divided by volts will tell you how many amps your pulling. If you have any two of the ratings, you can use the ohms law which will give you any one answer your looking for. Again I'm not sure this is the answer you are looking for. Keep reading your answers, because someone will probably have what your looking for. The answer will come from ohms law, if you have a copy of it.
2006-10-31 16:16:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
P=IE. Basic Electricity formula
2006-10-31 16:08:34 · answer #4 · answered by Anonymous · 0⤊ 0⤋
its as easy as PIE
well sort of.
Power(P) = Current(I) x Voltage(E)
If you know the current you multiply by the voltage to get the power.
You can use Ohm's Law to rearrange this into other possibilities.
P=I x R^2 if you know the current and the resistance
P=E^2 / R if you know the voltage and resistance
JeffM
2006-10-31 16:12:04 · answer #5 · answered by Jeff M 3 · 0⤊ 0⤋
you can multiply by your other #s and get the answers
2006-10-31 16:00:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋