At a party all those were married were there with their spouses. There were seven single people and thwo thirds of the men were married to three fifths of the women. How many were at the party? Show work.
2006-10-31 09:53:06 · 5 answers · asked by DJ Deep 3 in Entertainment & Music ➔ Jokes & Riddles
x=# of couples (men or women)
x(total)=total # of women
y(total)=total # men
x/x(total)=3/5; thus x(total)=5x/3
x/y(total)=2/3; thus y(total)=3x/2
x(total)+y(total)=2x+7
(5x/3)+(3x/2)=2x+7
19x/6=2x+7
7x/6=7
7x=42
x=6 (couples)
2(6)+7= 19 people.
2006-10-31 11:18:23 · update #1
There were 9 men, 6 married and 3 single (2/3 are married)
There were also 10 women, 6 married and 4 single (3/5 are married)
That makes 6 married couples and 7 single people.
Total of 19 people.
2006-10-31 10:02:54 · answer #1 · answered by Anonymous · 2⤊ 1⤋
2/3 of the men would have been 6, giving you 9 men. 3/5 of the women would have been 6, giving you 10 women. Total - 19 people at the party.
l like word problems.
2006-10-31 10:02:59 · answer #2 · answered by mxzptlk 5 · 2⤊ 0⤋
15
2006-10-31 10:06:50 · answer #3 · answered by DJMICK 2 · 0⤊ 1⤋
You make me think of my dad how he likes math. I hate math and percentages are my worst. You must be smart. I'm clueless! :-)
2006-10-31 09:59:58 · answer #4 · answered by Artsy 1 3 · 0⤊ 1⤋
you failed to mention if any of the couples were gay ?
2006-10-31 11:34:49 · answer #5 · answered by Anonymous · 0⤊ 1⤋