English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

a block and tackle is used to lift a load weighing 600 lb. the operator lifts the load a distance of 1.25 ft. by pulling on the rope with a force of 200 lb. over a distance of 4 ft.

a. input work= _____ft(lb)
b. output work=_____ft(lb)
c. efficiency of block & tackle= _____%

2006-10-31 07:02:38 · 2 answers · asked by Anonymous in Science & Mathematics Engineering

2 answers

W = F * d

a) 4 * 200 = 800
b) 1.25 * 600 = 750
c) b/a = 0.9375

2006-10-31 07:07:34 · answer #1 · answered by feanor 7 · 0 0

a) input work = 200 lb x 4 ft = 800 ft*lb
b) output work = 600 lb x 1.25 ft = 750 ft*lb
c) eff = out / input = 0.9375 or 93.375 %

friction accounts for the minor loss

2006-10-31 18:09:09 · answer #2 · answered by Mech_Eng 3 · 0 0

fedest.com, questions and answers