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2 answers

I think this will solve your problem:

mol / L - mol per litre.
Kg / m^3 - Kg per cubic meter.

Consider:
1mol / L
But 1m^3 = 1000L (÷ 1000 to get one L).
→ 1mol / L = 1mol / 0∙001m^3
→ 1mol / L = 1000 mol / m^3

Now measure the mass of the mole. You need to know it's mass for your calculation.
For an example, suppose it is 0∙95 of a Kg, then:
→ 1mol / L = 1000 mol / m^3
→ 1mol / L = 1000(0∙95)Kg / m^3
→ 1mol / L = 950 Kg / m^3

2006-10-29 22:47:23 · answer #1 · answered by Brenmore 5 · 0 0

I dont wanna do the calculations, you do it ( so which you will truthfully attempt). i will in simple terms say how get the style of mols of KOH... quantity (in litres) x molar concentration of KOH then, verify the ratio. interior the equation-- 2 molecules of KOH is had to react with a million molecule of H2SO4. with a purpose to get the style of mols of H2SO4, in simple terms dived the mols of KOH via 2 then in simple terms mols of H2SO4/quantity (in litres) = molarity of H2SO4 molarity is comparable to molar concentration

2016-10-20 23:54:06 · answer #2 · answered by templeman 4 · 0 0

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