English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I am drafting a report and need to evaluate the results. I think an RMS value for error is relative to a log scale, thus 1/2 size is 10x better, does anyone know this math relationship?

2006-10-27 16:37:39 · 4 answers · asked by J J California 1 in Science & Mathematics Engineering

4 answers

The RMS (root mean square) simply gives equal weight to positive and negative errors. It has nothing to do with the log scale.
Your question isn't complete. You have 1.0 mm or .5 mm error out of what measured value? If this is out of a 2 mm measured value there is a 50 % to 25 % error yielded . If the measured value is 1000 km, they are a wash and not significant; both 1.0 and .5 mm would yield about the same RMS error.

Here's aa site with more info -

http://www-stat.stanford.edu/~susan/courses/s60/split/node60.html

2006-10-27 16:59:52 · answer #1 · answered by Gene 7 · 0 0

RMS error implies a normal distribution of uncertainty. All you can say is that the uncertainty is twice as high in the 1.0 mm RMS error case compared to the 0.5 mm RMS error case.

2006-10-27 20:33:27 · answer #2 · answered by arbiter007 6 · 0 0

On right here they do no longer. I advise, it extremely is unlike we are at right here taking some style of spelling or grammar try. It annoys me on each and every occasion people %. aside questions or solutions which have spelling or grammatical blunders. Now on a professional rfile or something of that ilk, sure, spelling blunders subject me. If something is that considerable then somebody could desire to make an effort to do spell examine.

2016-12-16 15:38:36 · answer #3 · answered by ? 4 · 0 0

9.3%

2006-10-27 19:41:44 · answer #4 · answered by JD12201 2 · 0 0

fedest.com, questions and answers