My virus definitions expired and I keep getting these warnings that I am no longer protected.....I dont know if I want to shell out $40 a year for this service. Do you think its a scam, or am I gonna get slammed with viruses? I would think the basic program is enough protection.
2006-10-27 15:31:03 · 16 answers · asked by anonbealove 3 in Computers & Internet ➔ Software
Uninstall Norton and use AVG. It's good to have updated definitions, but there are too many free or cheap alternatives to be paying Norton $40 a year.
2006-10-27 15:38:00 · answer #1 · answered by robdob 2 · 0⤊ 0⤋
You get for what you pay for...I've always used Norton and the one time I tried a free version I got a virus within a month or 2. You get 3 downloads so splitting the price with 2 other people brings the price(which is expensive) down a lot...maybe 20-25$ a piece!
2016-03-28 09:43:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
As you can see from the answers, it is a matter of opinion.
Personally, I use free Antivirus programs, and have had no problems. There are many good ones available, AND if set to do so, will automatically update as needed. (Mine check for updates every time I boot the systems.)
I have a LAN (Local Area Network), and can therefore use more than 1 program to scan by using 1 machine for internet connections with the others connecting through that machine. That gives me 2 separate scans on everything.
I also only turn on the Internet machine when I need the internet, which cuts down the chances of "hacker" problems.
2006-10-27 16:03:46 · answer #3 · answered by f100_supersabre 7 · 0⤊ 0⤋
I've been happy with AVG free so far. and it's free the subscription version has some extras.
Ive tried the Norton and McAffee and they get those annoying pay more pop ups.
My dads and brother's Norton expired and they both got virus and Norton said they have the virus and needed the payment to remove it. I installed AVG free on my dad's machine and so far no problems.
2006-10-27 15:46:23 · answer #4 · answered by Robert F 7 · 0⤊ 0⤋
Personally, I pay for it and I feel it's worth it. However, I have a couple of friends and family members whose computers I work on. They're not always up for paying for some of this preventative stuff so for anti virus I have them use AVG. It's free for home use and it updates in the background like any other program. Never had a virus on any of the machines that it's used on so if you're not doing anything overly dangerous then I'd say go for something free.
AVG:
http://www.grisoft.com/doc/40/lng/ww
2006-10-27 15:40:41 · answer #5 · answered by Patrick 2 · 0⤊ 1⤋
You should run an anti virus program on a computer ALWAYS!! However, there are a number of ones out there that do just as good as the big boys without all the load on your system. I use AVG free myself and find it works very well. You can download it at www.download.com
2006-10-27 15:41:22 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I think it is the only thing worth paying for. Viruses change regularly and you need updated protection. One virus and your drive wiped out. Prevention for the price of a magazine subscription.
2006-10-27 15:35:32 · answer #7 · answered by sdh0407 5 · 0⤊ 1⤋
AVG is free and they have almost daily updates for virus protection and mine has caught a bunch of viruses i never knew i even had
2006-10-27 16:52:59 · answer #8 · answered by Terryn M 3 · 0⤊ 0⤋
I think so , it's what I use , Norton has caught alot of different things , where others failed to do so. There's also a program trendmicro.com , I have a friend that just does that daily . I still prefer Norton.
2006-10-27 15:35:46 · answer #9 · answered by ridingthestorm_out 4 · 0⤊ 2⤋
No. As long as you don't open a bunch of junk mail and websites on your computer you won't get a virus. I have never had a virus on my computer, nor have I ever had a anti-virus on my computer either. Just don't click on ads or if your e-mail says it is suspicious then don't open it unless you know the person you are getting an e-mail from.
2006-10-27 15:33:59 · answer #10 · answered by lil_critter33 2 · 1⤊ 2⤋