Be careful...VERY slippery slope. I see it as a lose, lose situation. First of all, if it works out, you're going to see that person EVERYDAY. I wouldn't want that. Secondly if it doesn't work out it's very awkward. Do you want to still see someone you used to date that much? Either way you lose. Just my opinion.
2006-10-27 07:54:39
·
answer #1
·
answered by jim 6
·
0⤊
0⤋
Well when i dated someone who worked with me i found that the whole department knew within a few days so there was rumours everywhere. It was also extremely awkward when we broke up and so i suggest it's too much hassle although i know others who work together and date and get on well.
2006-10-27 14:53:45
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
It is usually a bad idea. The other employees will see that person as being favored and they will all feel that they are treated unfairly.
It also creates an uncomfortable situation if the relationship ends. Especially if it ends badly.
Take care,
Troy
2006-10-27 14:53:18
·
answer #3
·
answered by tiuliucci 6
·
0⤊
0⤋
Always have to watch dating your employees. If things don't go right she may come back and say that you sexually harassed her and sue you. Word to the wise.
2006-10-27 14:52:28
·
answer #4
·
answered by fijisun 2
·
0⤊
0⤋
HELL NO
then how about it does not work out
and shitt hits the fan
how are you gonna fire her
non no nonononoo
dont do it
2006-10-27 14:53:19
·
answer #5
·
answered by melanni 2
·
0⤊
0⤋
I just prefer to sleep with them.......dating complicates things
2006-10-27 14:51:55
·
answer #6
·
answered by Paul M 3
·
0⤊
0⤋
No, never! Usually causes problems.
2006-10-27 14:50:52
·
answer #7
·
answered by Premo Mom 5
·
0⤊
0⤋
At the time its all great, but what if you brake up what then?
2006-10-27 14:51:24
·
answer #8
·
answered by 'Cause I'm Blonde 5
·
0⤊
0⤋
who works for you, or works with you, dont!!! not a good idea... dont eat where you poof...
2006-10-27 14:52:33
·
answer #9
·
answered by "sehz" 1
·
0⤊
0⤋
No baby that trouble.
2006-10-27 14:54:56
·
answer #10
·
answered by Cherry 2
·
0⤊
0⤋