a cyclist is coasting at a steady speed of 12m/s but enters a?

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a cyclist is coasting at a steady speed of 12m/s but enters a?

a cyclist is coasting at a steady speed of 12m/s but enters a muddy stretch where the effective coefficient of friction is 0.60. The muddy stretch lasts for 11 m. What is the cyclists speed upon emerging from it.

2006-10-25 21:04:59 · 4 answers · asked by 3ajeeba_q8 2 in Science & Mathematics ➔ Physics

4 answers

12 m/s, because he starts peddling.

2006-10-25 21:09:58 · answer #1 · answered by tgypoi 5 · 0⤊ 2⤋

isnt it just 12 times by 0.60

2006-10-26 04:14:11 · answer #2 · answered by Bobby B 2 · 0⤊ 0⤋

a = -0.6*9.8m/s^2
v^2 - v0^2 = 2as
v^2 = 144 m^2/s^2 - 2*11*0.6*9.8m^2/s^2
v^2 = (144 - 129.362)m^2/s^2
v = 3.826 m/s

2006-10-26 04:46:43 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋

Do your own homework and learn something for once

2006-10-26 04:07:50 · answer #4 · answered by Anonymous · 0⤊ 2⤋