I am so confused on this question:
Two perpendicular lines intersect on the y-axis. The equation of one line is 4y-x-24=0. Determine the equation of the other line.
2006-10-25 18:10:27 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
you solve for y and since you want a perpendicular line, you simply use the opposite reciprocal of the slope from your original sentence
2006-10-25 18:18:41 · answer #1 · answered by jtarango_1 2 · 0⤊ 0⤋
First, write the equation of the first line in the form y=mx+b. You get y = x/4 + 6.
Given a line of slope m, a line perpendicular to it has slope -1/m. Therefore, the second line has an equation of the form y = -4x + b.
To determine b, use the fact that they intersect on the y-axis. Plug x=0 into both equations. For the first line, you get y=6, and for the second line, you get y=b. You need these to be equal for the lines to intersect on the y-axis, so set b=6.
In conclusion, the equation of the other line is y = -4x + 6.
2006-10-26 01:13:57 · answer #2 · answered by James L 5 · 0⤊ 0⤋
slope of the known line is 1/4 and y-int=6, so the other slope is -4 cause perpendicular lines have the negative reciprocal slopes of each other
they both have the same y-intercept,
so y=-4x+6 is the other line
2006-10-26 01:14:38 · answer #3 · answered by Mech_Eng 3 · 0⤊ 0⤋
Isolate the variables
4y-x=24
y-x=6
y= 3
x= -3
To be perpendicular they have to be opposite...
(I think that's it...)
2006-10-26 01:23:41 · answer #4 · answered by Sandi 3 · 0⤊ 0⤋