It took the braking force of 1000 Newtons a distance of 50 meters to stop a car. What was the kinetic energy of the car before the braking was started?
Explain answer please.
2006-10-25 18:03:02 · 6 answers · asked by ??? 2 in Science & Mathematics ➔ Physics
K.E. = (1/2)mv0^2
v^2 - v0^2 = 2as
-v0^2 = 2as = 2(-F)s/m
v0^2 = 2as = 2Fs/m
mv0^2 = 2Fs
(1/2)mv0^2 = Fs
K.E. = Fs
K.E. = (1000 N )(50 m)
K.E. = 50,000 Nm
K.E. = 50,000 Joules
2006-10-25 18:49:52 · answer #1 · answered by Helmut 7 · 0⤊ 1⤋
The kinetic energy=F*S
KE=1000*50
KE=50,000 Joules
2006-10-26 02:24:01 · answer #2 · answered by mekaban 3 · 0⤊ 1⤋
force x distances travelled = energy due to braking force
By conservation of energy,
energy due to braking force = kinetic energy of car in motion
2006-10-26 12:28:41 · answer #3 · answered by weiqiang c 1 · 0⤊ 1⤋
(final velocity)^2 -(initial velocity)^2 = 2*(acceleration)*(displacement)
0-(initial velocity)^2 = 2(acceleration0*50
= 2(force)/mass*50
= 2*1000/mass*50
1/2*mass*(ini velocity)^2 = 1000*50 = 50000 = kinetic energy before breaking!
2006-10-26 01:27:43 · answer #4 · answered by !kumar! 2 · 0⤊ 1⤋
Kinetic energy = Potential energy
mgh = 1/2 mv^2
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Kinetic energy is output of potential energy
2006-10-26 01:24:34 · answer #5 · answered by Anonymous · 0⤊ 1⤋
You need more information to solve this problem, such as the stopping time or the mass of the car.
2006-10-26 01:32:20 · answer #6 · answered by William G 1 · 0⤊ 1⤋