Can you guys help me with a surface area problem?

Question

this isnt homework but its a problem ive always had a thing with :

what is the total surface area of a box whos dimensions are 2b x b x b?

Answer 1

total surface area is found by adding surface area of individual surfaces. since there are 6 surfaces having dimensions 2b x b x b, total surface area is given by;

dimensions of atleast two surfaces is b x b and so surface area is 2 x(b x b).

remaining 4 sides dimensions are 2b x b and hence surface areas will be 4 x(2b x b).

hence total surface area of the box is 4 x(2b x b) + 2 x(b x b) = 10 b^2.

Answer 2

I'm assuming the box is closed, so it has 6 faces. Two of them have area b*b, and the other four have area 2b*b. Therefore the total area is 2*b^2 + 4*2*b^2 = 10b^2.

Answer 3

The box has 6 sides

the top and bottom are 2b by b, so 2b^2 area is multiplied by 2
for sum of 4b^2

the each end has area b^2 , sum of 2b^2

this leaves two side each having 2b by b, for a sumed area of 4b^2

barring any mistakes the total surface area is 10b^2

Answer 4

let's just look at the surface area

of top = 2b * b
of front = 2b * b
of side = b * b

the bottom, back, right will be correspondingly the same, so
we just double the sum of top, front, and side area

total surface area S = 2*[2b^2 + 2b^2 + b^2] = 10b^2

Answer 5

a box should have six surfaces, right? then easy. just find the area of each face by multiplying the two sides. then plus the area of all the surfaces

Answer 6

4(2b x b) + 2(b x b)

10b squared.

Answer 7

10 b square

Answer 8

so slice the barrel so the slices would cover the roof how thick are the slices?a circle has 78.54% the area of the square that fits around it does this help?

Answer 9

10b squared