logarithms?

0 ⤊

log(base 4)x=5/2

2006-10-25 16:22:48 · 3 answers · asked by Lauren 1 in Science & Mathematics ➔ Mathematics

3 answers

4^(5/2)=x
x=32

Hope that helps!

2006-10-25 16:25:09 · answer #1 · answered by D 3 · 0⤊ 0⤋

exponentiate both sides with base 4:

4^(log(base 4) x) = 4^(5/2)

a^(log(base a) x) = x, so you have

x = 4^(5/2)

a^(xy) = (a^x)^y, so this becomes

x = (4^(1/2))^5
=> x = 2^5
=> x = 32.

2006-10-25 23:26:07 · answer #2 · answered by James L 5 · 0⤊ 0⤋

log(4)x = (5/2)

this converts to

4^(5/2) = x

x = (4^(1/2))^5
x = 2^5
x = 32

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another way to do this is

log(4)x = (5/2)
(log(x))/(log(4)) = (5/2)
log(x) = (5/2)log(4)
log(x) = log(4^(5/2))
x = 4^(5/2)
x = 32

2006-10-25 23:28:33 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋