Why isn't x2+y2(to the second power)=8 a quadratic function?

Question

Thanks for the help.

Answer 1

because it's got the y to the second. a quadratic would have an x squared, then a regular x, then a number of some sort. they need to be set to zero to solve. they would not have two different variables or two variables to the second

Answer 2

x^2 + x -12 Now locate 2 numbers such that their product is -12 and their sum is +a million How do you are trying this? answer is - locate the top factors of 12 using the LCM calculation approach So 12 = 2 * 2 * 3 From right here you have the probabilities as 2 and 2*3 i.e. 2 and six 2*2 and 3 i.e. 4 and 3 the version of two & 6 is two so it is ruled out the version of four & 3 is a million so this might artwork for us Having gotten that be conscious that product is unfavorable (-12) however the version is beneficial ( +a million) So considered one of four and 3 could be unfavorable and the different beneficial 4 gets to be beneficial and 3 as unfavorable by way of fact the version might then be +a million So we get +4 and -3 we can rewrite the quadratic function as x^2 +4x - 3x - 12 = x(x+4) -3(x+4) = (x-3)(x+4) those are your factors and thats your answer. its all quite common . i'm particular that once you re study the financial disaster in the e book from the beginning up you would be grasp at it your self after extremely prepare. sturdy good fortune.

Answer 3

It depends how you define 'quadratic'. My dictionary defines it as 'involving the square and no higher power of the unknown quantity'. Since your equation does not involve powers higher than 2 (ie squares), the naccording to this definition x*x + y*y =8 is a quadratic equation.

That said, it is not the sort of quadratic that is most common. These tend to be of the form ax^2+bx+c=d. Your equation is not of this form since it has both x0-squareds and y-squareds in it. Therefore, it is not suitable for the quadratic formula and you need to use more complicated techniques to solve it (as well as a second equation).

Also, some textbooks define a 'function' as having y by itself on the left hand side. Using this definition, to get a function you would need to rearrange the equation as follows:

x^2+y^2 = 8
<=> y^2 = 8 - x^2
<=> y = +/- sqrt(8 - x^2)

I hope you make sense of my notation. +/- is plus or minus and sqrt () is square root of everything in the brackets.

Since this formula has a square root in it, it is not a quadratic, but it depends on your definitions of both 'quadratic' and 'function'. Hope this helps.

Answer 4

a quadratic function should be of the form ax^2+bx+c=0 where a is non zero

Answer 5

quadratic equation means the highest power in the equation is "2"
if you rewrite your equation

y=sqrt(8-x^2)

x^2 is in the square root. so thats why it is not a quadratic function

Answer 6

Because a function has only one value of x for each value of y. Your equation is a circle.

Answer 7

because you need 3 variables, you only have 2.

Answer 8

Because some crazy wacko said it wasn't many many years ago, and we just believe it.

Answer 9

because there are two variables.