then whats the difference of gravitational attraction between the two stars, if its stronger then how much stronger, is it weaker? im confused by this concept, and if its stronger is it a little stronger, or a lot stronger?
2006-10-25 15:39:00 · 5 answers · asked by future doc 1 in Science & Mathematics ➔ Astronomy & Space
Hi. There would be no difference in attraction. Mass is the sole criteria for gravity. If you shrunk it enough it would become a black hole, but the gravity at Earth's distance would be identical, it would still take a year to revolve.
2006-10-25 15:40:16 · answer #1 · answered by Cirric 7 · 2⤊ 0⤋
There would be no change in gravity outside the limits of the star's former outer layer since gravity depends on mass. But since the size is smaller, it would be possible to get closer to the center of mass than before it shrunk. At a place that was formerly inside the star but now outside the star, gravity would be stronger according to the inverse square of the distance part of the gravity expression, GMm/R^2.
2006-10-25 23:19:18 · answer #2 · answered by campbelp2002 7 · 1⤊ 0⤋
The integral equations for derivation of gravitational attraction provide the same answer whether the Sun is the size it is, or if the Sun's mass were completely concentrated in a point.
2006-10-25 22:51:01 · answer #3 · answered by arbiter007 6 · 1⤊ 0⤋
It's the same at a distance, such as its effect on Earth, but much stronger for a body at the small sun's surface since the R in the grav. equation (F=Gm1m2/R^2) is so much smaller.
2006-10-25 22:52:15 · answer #4 · answered by kirchwey 7 · 0⤊ 0⤋
Yes..........You are confused.
2006-10-25 22:41:13 · answer #5 · answered by flagnsnarf 2 · 0⤊ 0⤋