Two jets leave an airport at the same time in opposite directions. The first jet is traveling at three hundred forty one mph and the other at three hundred thirty two mph. How long will it take for the jets to be 1,616 miles apart? Round your answer to the tenths place.
2006-10-25 15:21:08 · 4 answers · asked by K&E4life 1 in Science & Mathematics ➔ Chemistry
HI!
You actually have a D=RT problem. The plans are travelling in opposite directions (DRAW A PICTURE) so the rate that they are going apart is 341+332 mph. or 673 MPH = R.
D = 1616 MILES, T = ?
D = R T
so T = D / R
= 1616 / 673 = 2.40 HOURS
0.40 HOURS = 0.40 * 60 MIN. = 24.1 MIN.
So the answer is 2 Hrs 24.1 Min.
2006-10-25 15:46:07 · answer #1 · answered by DANNOMathWHIZ 1 · 0⤊ 0⤋
Since the planes are going opposite direction, you have to add their speeds together:
341 + 332 = 673 mph
this means that every in 1 hour their distance form each other will be 673 mile.
now divide 1616 by 637:
1616/673 = 2.40
1hour = 60 minutes
0.40 X 60 = 24 minutes
therefore the planes will be 1,616 miles away from each other after 2 hours and 24 minutes.
2006-10-25 22:33:33 · answer #2 · answered by smarties 6 · 0⤊ 0⤋
They are separating at 341+332 = 673 mph.
Divide the distance required by the speed of separation.
2006-10-25 22:25:20 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋
2hr 45 min or so
2006-10-25 22:24:41 · answer #4 · answered by Douglas R 4 · 0⤊ 1⤋