to be equal 27. e.g 5+7+15 = 27 Please can someone tell me
Thanks
2006-10-25 14:23:53 · 8 answers · asked by Bobby 1 in Science & Mathematics ➔ Mathematics
ps. only three numbers can be use
Sorry
2006-10-25 16:46:01 · update #1
You want the six ways? Can you only use 3 numbers?
3 + 9 + 15 = 27
5 + 7 + 15 = 27
6 + 9 + 12 = 27
7 + 8 + 12 = 27
7 + 9 + 11 = 27
These are all the combinations of 27 using 3 numbers... if you can use more or less you also have:
12 + 15 = 27
3 + 5 + 7 + 12 = 27
3 + 5 + 8 + 11 = 27
3 + 7 + 8 + 9 = 27
5 + 6 + 7 + 9 = 27
2006-10-25 14:26:24 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
3+9+15= 27
5+7+15= 27
6+9+12= 27
7+9+11= 27
8+7+12= 27
0+12+15= 27
2006-10-26 09:02:11 · answer #2 · answered by mich 2 · 0⤊ 0⤋
15 + 9 + 3
15 + 7 + 5
12 + 9 + 6
12 + 8 + 7
12 + 7 + 5 + 3
11 + 9 + 7
11 + 8 + 5 + 3
11 + 7 + 6 + 3
9 + 8 + 7 + 3
9 + 7 + 6 + 5
That's 10, there may be others. When you do this type of problem you want to have some method, otherwise you will tend to go over the same answers again and again and miss others. I started with the bigger numbers and went down.
2006-10-25 21:28:37 · answer #3 · answered by sofarsogood 5 · 0⤊ 0⤋
1. 9+11+7=27
2. 5+6+9+7=27
3. 8+12+7=27
4. 6+3+11+7=27
5. 7+3+6+11=27
6. 15+3+9=27
many ways
2006-10-25 21:40:30 · answer #4 · answered by rjl2382 2 · 0⤊ 0⤋
15 + 12
15 + 9 + 3
15 + 7 + 5
12 + 9 + 6
12 + 8 + 7
11 + 9 + 7
Those are 6 combinations that add up to 27.
2006-10-25 21:36:47 · answer #5 · answered by Draco Moonbeam 3 · 0⤊ 0⤋
12+15
7+9+11
3+6+7+11
3+5+8+11
3+7+8+9
5+7+15
2006-10-25 21:30:34 · answer #6 · answered by Philip H 2 · 0⤊ 0⤋
5+7+15
3+9+15
7+9+11
12+7+8
6+9+12
12+15
2006-10-25 21:34:07 · answer #7 · answered by upinbubbles 2 · 0⤊ 0⤋
15+3+9
5+7+15
11+9+7
9+6+12
8+12+7
I don't think there is a 6th one unless you can use more than 3 numbers...
2006-10-25 21:33:55 · answer #8 · answered by iceclimbers1 2 · 0⤊ 0⤋