A bug sits on the rim of a 78 rev/min?

Question

record that is 12 in in diameter. The record moves from rest to its final angular speed
in 2.91 s.

What is the bug's centripetal acceleration 1.5 s after the bug starts from rest (in m/s^2)?
1 in. = 2.54 cm

Possibly?
ac = v^2/r

Answer 1

Centripetal acceleration = r*w^2, where w is the angular velocity at that moment.
The final angular velocity of the record = 78*2*pi/60 rad/s = 8.168 rad/s.
Assuming constant acceleration, the angular velocity of the record 1.5 sec after it starts = 8.168*1.5/2.91 = 4.21 rad/s
Thus the centripetal acceleration = 6*2.54*4.21^2 = 270.16 cm/s^2 = 2.7016 m/s^2