(x+2)(x^2+5x-2)
2006-10-25 14:18:05 · 8 answers · asked by Jeff W 1 in Science & Mathematics ➔ Mathematics
That isn't an equation. Is it supposed to =0?
If that's so, then you can solve as
x + 2 = 0 or x^2+5x-2 =0
The first gives you a simple value of x,
for the second use
x = -b + or - sqrt(b^2 - 4ac)
with a = 1, b = 5, c = -2.
So you get 3 answers altogether.
2006-10-25 14:22:27 · answer #1 · answered by Hy 7 · 0⤊ 0⤋
This is not an equation. An equation will EQUAL something. Get it?
For example, x + 5 = 10 is an equation; 4 + 5 = 9 is an equation.
Your question has two factors:
Factor 1 = (x+2)
Factor 2 = (x^2+5x-2)
Simply multiply the two factors and you're set.
Guido
2006-10-25 21:27:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(x+2)(x^2+5x-2)
This isn't an equation. Do yo umean
(x+2)(x^2+5x-2) =0 ?
if so, x=-2 is 1 root
the other 2 can be found from
x=(-5+/-sqrt(25+8))/2=(-5+/-sqrt(33))/2
x=.372
x=-5.37
2006-10-25 21:26:28 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
Distributive property:
x^3 +5x^2-2x + 2x^2+10x-4
Combine like terms and put in descending order of x's:
x^3+7x^2+8x-4
There ya go...
2006-10-25 21:20:56 · answer #4 · answered by Shaun 4 · 0⤊ 0⤋
that isn't a equation. What does this equal? Is it zero and do u want people to solve for the roots? be more specific.
2006-10-25 21:21:50 · answer #5 · answered by upinbubbles 2 · 0⤊ 0⤋
just as Shaun said, distributive property but you have to add the exponents for if they have similar bases like 'x'
2006-10-25 21:22:53 · answer #6 · answered by genji 3 · 0⤊ 0⤋
X^2 + 5X - 2
X + 2
----------------
2X^2 + 10X - 4
5X^2 - 2X + X^3
---------------------------
Answer
X^3 + 7X^2 + 8X - 4
Regards,
Zah
2006-10-25 21:33:42 · answer #7 · answered by zahbudar 6 · 0⤊ 0⤋
use distributive property and yadda yadda
2006-10-25 21:25:07 · answer #8 · answered by VOOL 5 · 0⤊ 0⤋