need help with algebra problems...?

Question

the directions say to find the quotient(spelling?)
here is one problem that I am having trouble with:

15t - 25 over -5

and another:

-3a + 16 over 4

I don't get how to work these problems
can someone show me how to work these problems please?

thanx

Answer 1

1) all the numbers are divisible by 5 so divide everything by 5 and you get 3t-5

2) 4 can go into 16 four times so divide 16 by 4 and you get 4 on the top and 1 left on the bottom but since -3 isnt divisible by 4 then that has to be left as a fraction and your left with
-3a/4+4

Answer 2

(15t - 25) / (-5)

factor out the 5 on the numerator, and cancel out a five from the denominator and numerator, that gives you
-3t + 5


(-3a + 16) / (4)

do the same as in the first problem. the final answer would be..

((-3a)/4) + 4

Answer 3

Here you go, step by step
(15t - 5)/5 = Divide by 5
3t - 1 = Move the 1 across the equal sign (switching signs)
3t = +1 (divide both sides by 3)
t = 1/3 ( one third fraction)

(-3a + 16) / 4 = divide by 4
(-3/4a) + 4 = move the four across the equal sign (becomes negative)

(-3/4a) = -4 (multiply both sides by four to get rid of the fraction mixed with the unknown)

-3a = -16 divide both sides by (-3) to isolate the unknown, the negatives will cancel out

a = 5 (1/3)

Answer 4

Adding Multiplication Sign: -3*a+16/4
Poly Parsing: -3*a+16/4
Splitting -3*a+16/4
-3*a + 16/4
[Left Side]Poly Parsing: -3*a
Poly Parsing: 3*a
Multiply Term 3 with Term a equals Term 3a
AddTerm: Term (3a)
Poly = 3a
Because of the minus sign 3a becomes -3a

Poly = =-3a
Repace with Reduced Left Side
-3*a + 16/4
-3a + 16/4
[Right Side]Poly Parsing: 16/4
Divide Term 16 with Term 4 equals Term 4
AddTerm: Term (4)
Poly = 4
Repace with Reduced Right Side
-3*a + 16/4
-3a + 4
Poly Adding -3a with 4...
AddTerm: Term (-3a)
AddTerm: Term (4)
... -3a+4
Poly = -3a+4
The problem to solve is: -3a+16/4
-3a+4
The problem to solve is: -3a+16/4
-3a+4
Now let's simplify the i's to get our final answer:

Term #1 (-3a) doesn't contains an i. There's no need to simplify.
AddTerm: Term (-3a)
Term #2 (4) doesn't contains an i. There's no need to simplify.
AddTerm: Term (4)
The problem to solve is: -3a+4

Answer 5

(15t - 25)/-5 = -3t +5
just divide both terms by the term in the denominator
(-3a + 16)/4 = -3/4t + 4 = -0.75a + 4

Answer 6

well quotient is the answer so yea
um i got 15t+5
and -3a+4

Answer 7

for the first one simply simplify
3t - 5

for the second one simply simplify
since u cant divide -3 into 4 evenly u leave it as a fraction
-3a/4 +4

Answer 8

factor out a 5 from the top leaving
5(3t-5)/-5
5/-5 becomes -1
leaving -1(3t-5)=-3t+5

Answer 9

Are you trying to reword the problem to
t = blahblahblah
?

Answer 10

I don't know how to do this but its not cheating if you don't know how to do it she's asking how to do it not asking for direct answers.