If color is seen on an object because light is shining on it, why is it always the same color to the naked eye

Question

even if the shade is a different shade, why is it still the same color?

Answer 1

Actually the color of an object is because of the portion of the light spectrum (color) that is reflecting from it. All the other colors are absorbed. Whether the light intensity is high or low, the same color will be reflected from the object.

Answer 2

Other than shade variance, the reason that red is still red, blue is still blue etc. is because unless there is the absence of light the eye will still see color.

It isn't really light "shining" on it, color is seen when light fragments reflect off of an object and back to the eye. That's why colors "pop" more when there's more light absorbed or reflected from them (ie blue in dim light looks different than blue in bright light).

Answer 3

It isn't. If pure white light shines on an object then the colour it reflects is said to be its true colour. If however you view that same object in a different coloured light, it will not appear to be the same colour. For example a yellow object viewed under monochromatic blue light will appear to be black, because blue light contains no yellow, so there is nothing to be reflected. A yellow object seen in monochromatic yellow light will appear to be white because 100% of the light falling on it will be reflected and your brain will adjust to make it appear white. Try looking at daffodils under sodium lighting and you will see.

Answer 4

Things appear a certain color because they reflect only one particular wavelength of light. If the light shining on it does not contain that wavelength, the object will appear black. Happily, most light we use contains all wavelengths we can see..............

Answer 5

Hi. Take a red object out in the moonlight and you'll discover that what you are saying just is not true. Red is black in the moonlight.

Answer 6

wavelength remains constant