Anyone up for this one..?

Question

You have 280 balesto haul. your turck and trailer weighs 2150 empty. you load 56 bales and your weight is 6182.
A. what precent of the bales did you get in the first load?
B. how many loads will it take to haul all the bales?
C. what is the average weight of the bales.

Answer 1

You basically just need to figure out what the question is asking you for and then write the correct equation...

A. What percent of the bales did you get in the first load? Percent is calculated by dividing the bales loaded (56) by the total bales (280) and then multiplying by 100 to get a percent.

56 / 280 * 100 = 1/5 * 100 = 20%

B. How many loads will it take to haul all the bales? If you got 20% in one load, and you need 100%, just divide to get the number of trips.

100 / 20 = 5 trips

You can also take total bales (280) divided by bales in one load (56).

280 / 56 = 5 trips

C. What is the average weight of the bales? Average weight is total weight divided by the number of bales. Adding 56 bales to the truck raises the weight from 2150 to 6182. That means the bales weigh 4032 (6182 - 2150). The average weight per bale is:
4032 / 56 = 72

So each bale weighs 72 on average. (lbs, kgs, I don't know)

Answer 2

A.56/280 *100=20%
B.280/56=5
C.(6182-2150)/56=72

Answer 3

A. 100*56/280
B. total bales / bales per load = 280/56, rounded up to the nearest integer (it will already be an integer in this case though)
C. (weight full - weight empty)/(bales loaded) = (6182-2150)/56

Answer 4

A) 100(56)/280

B) 280/56

C) (6182 - 2150)/56

Answer 5

a 20%
b 5
c 72

Answer 6

a.) 20%
b.) 5 loads
c.) averae weight: 72 units.

Answer 7

20 %,5 loads, 72lbs