help
2006-10-25 11:38:27 · 5 answers · asked by lostinmath 1 in Science & Mathematics ➔ Mathematics
Factor out an x:
x(2x^3 - 3x^2 - 4x)
Now it is obvious that if you divide by x you get:
2x^3 - 3x^2 - 4x
Alternatively, just take each term and divide it by x:
2x^4 / x + 3x^3 / x + 4x^2 / x
You'll get:
2x^3 + 3x^2 + 4x
2006-10-25 11:42:29 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
To divide by x, divide each term by x. The terms are 2x^4, -3x^3, and -4x^2. To divide x to some power by x, just lower the power by one. So for your first term, 2x^4, you have x to the power of 4. Lower that by one, and you get 2x^3. Do that for all terms, and you get:
2x^3 - 3x^2 - 4x (x to the power of 1 is just x).
2006-10-25 18:47:16 · answer #2 · answered by Martoon 1 · 0⤊ 0⤋
2x^4 / x - 3x^3 / x - 4x^2 / x = 2x^3 - 3x^2 - 4x.
Use the fact that x^a / x^b = x^(a-b).
2006-10-25 18:41:42 · answer #3 · answered by James L 5 · 0⤊ 0⤋
Cool how you got the exponents to appear like that. Lemme see if I can figure out how this is done....
76°
x³ + 2x² + 3x
¾
±4
mañana
Mötley Crüe
Got it! Tedious, though. Man, if you can work with this character set, I can't understand why you aren't a whiz at math. :)
2006-10-25 19:03:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x^3-3x^2-4x
2006-10-25 18:41:28 · answer #5 · answered by raj 7 · 0⤊ 0⤋