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lim (x^a-1)/ (x^b-1)
x->1

2006-10-25 11:23:11 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

As x --> 1 numerator --> 1^a - 1 = 1 - 1 = 0
Similarly for the denominator
0 / 0 is undefined, so use l'Hopital's Rule

derivative of numerator = a x^(a-1)
derivative of denominator = b x^(b-1)

As x --> 1 a x^(a-1) --> a
As x --> 1 b x^(b-1) --> b
So limit is a / b

2006-10-25 13:25:55 · answer #1 · answered by p_ne_np 3 · 0 0

You don't need L'Hosptial's rule for this. 1 to any power is 1. So, as x -> 1, the numerator and denominator will both go to 1, and the result will be 1.

2006-10-25 18:29:15 · answer #2 · answered by Dave 6 · 0 1

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