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When sodium chlorate(I) (or hypochlorite) is acidified, a classic type of reaction called disproportionation occurs, which is nothing to do with HCl being a reducing agent. Cl in +1 oxidation state oxidises and reduces itself, ending up as Cl2 (chlorine gas) and (ClO3)- ions, or chlorate(V).

The ionic equation is:

4H+ + 5ClO- ----> 2Cl2 + (ClO3)- + 2H2O

2006-10-29 07:16:44 · answer #1 · answered by Gervald F 7 · 0 0

I am not so used in identifying elements and compounds but I am good at chemical reactions. Ok lets take Calcium carbonate as the mystery carbonate. When Calcium carbonate reacts with HCl here's the reaction. CaCO3 + Hcl -----> CaCl2 + H2O + CO2 CaCl2 is soluble and hence wont appear as precipitate CO2 will liberate so you're left with CaCl2 + H20 Now if you add NaCO3 to this solution, little bits of white powder appears. Which means the solution contains calcium chloride which means the carbonate given is of calcium. Similarly if you it is barium carbonate. You will finally be having BaCl2 + H20 So now if you add H2SO4 to this solution you will be having BaSo4 which is a white precipitate which means it is barium carbonate. Like this you can identify the other carbonates too

2016-05-22 13:45:45 · answer #2 · answered by Anonymous · 0 0

NaClO is an oxidizing agent and HCl is a reducing agent, so:

NaClO + 2HCl --> Cl2 + NaCl + H2O

2006-10-25 11:10:43 · answer #3 · answered by Dimos F 4 · 0 2

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