I know the older one is named Sean Preston Spears Federline or something.
2006-10-25 10:22:27 · 13 answers · asked by tinkerbelle3089 1 in Entertainment & Music ➔ Celebrities
the other is Jayden James
2006-10-25 10:25:27 · answer #1 · answered by rockthis102 3 · 2⤊ 0⤋
Sean Preston and Sutton Pierce Spears Federline
2006-10-25 11:14:29 · answer #2 · answered by mkay_gonzalez 2 · 0⤊ 0⤋
Jayden James is the 2nd ones name and Sean Preston is right for the first one.
2006-10-25 10:25:36 · answer #3 · answered by schell_75 3 · 0⤊ 0⤋
Sean Preston is the first one and Jayden James is the recent and second one.
2006-10-25 10:31:16 · answer #4 · answered by baramler 2 · 0⤊ 0⤋
She has Sean Preston and then there was Sutton Pierce...but apparently his name is actually Jayden James. Personally Sutton is a better name.
2006-10-25 11:26:01 · answer #5 · answered by rockstar_nikki16 2 · 0⤊ 0⤋
~Sean Preston & Sutton Peirce{Jayden James?}
*Step kids Kori and Caleb, with Shar Jackson
2006-10-25 12:12:50 · answer #6 · answered by pattiwish 4 · 0⤊ 0⤋
Her other son's name is Jayden James Federline.
2006-10-25 10:25:27 · answer #7 · answered by Anonymous · 1⤊ 0⤋
I don't remember as when they told us we couldn't really care less. They are her kids and we have no interest in them or her or the k-fed. All of them should just quietly go away and live a life out of the public eye. We are not interested. Her time is past, he has no talent and is laughable. and the poor kids should get to have a normal life. Her 15 minutes are up. Thanks
2006-10-25 10:27:14 · answer #8 · answered by Anonymous · 0⤊ 1⤋
lol yeah i assume sometimes i think of celebrities attempt to bypass over and out finding out on a attractiveness who the heck needs Pilot inspector as a attractiveness? i think of the names she chosen are great yet merely being real approximately it, the different names you listed are extraordinary
2016-12-08 21:14:46 · answer #9 · answered by ricaurte 4 · 0⤊ 0⤋
britney spears who? lmao
2006-10-25 10:31:15 · answer #10 · answered by goingfasterbmw 3 · 0⤊ 0⤋