Enrique puts 12% of his monthly paycheck in an IRA. If he invests $72 in his IRA, how much was his paycheck?
2006-10-25 09:12:44 · 6 answers · asked by shy l 1 in Science & Mathematics ➔ Mathematics
12%= .12
and if .12 of his paycheque is $72
then .12xpaycheque = 72
72/.12 = paycheque
=$600
2006-10-25 09:18:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
12 * P = 72 Then you divide both sides by 12
12/12 * P = 72/12
P= 600/1
2006-10-25 10:59:50 · answer #2 · answered by SarinaAnn 4 · 0⤊ 0⤋
A better way to state this is 12% of what is $72.
So, .12 x N = 72
Divide by .12
N=600
So, his paycheck is $600
2006-10-25 09:53:17 · answer #3 · answered by danjlil_43515 4 · 0⤊ 0⤋
12% is equal to 12/100 = 0.12. If Enrique's paycheck is set equal to x, then 0.12x = $72, so x = $72/0.12 = $600.
2006-10-25 09:18:22 · answer #4 · answered by DavidK93 7 · 0⤊ 0⤋
12%=.12
.12X=72
X=600.
His paycheck was 600 bucks. Move the decimal two places to the left and then it's a simple algebra problem.
2006-10-25 09:20:43 · answer #5 · answered by Nate 2 · 0⤊ 0⤋
12% of x = 72
or .12*x=72
x=72/.12
x=600 bucks
2006-10-25 09:19:27 · answer #6 · answered by JP 2 · 0⤊ 0⤋