x^6/x^3
8x^-2y^5z^-3
(3x^2y)(-8xy^4
show work please thanks
2006-10-25 09:01:35 · 4 answers · asked by yankee_914 1 in Science & Mathematics ➔ Mathematics
The property of exponents states that x^a/x^b = x^(a-b)
x^6/x^3 = x^(6-3) = x^3
The property of exponents states that x^-a = 1/x^a
8x^-2 y^5 z^-3
(8y^5)/x^2z^3
The property of exponents states that (x^a)(x^b)=x^(a+b)
(3x^2y)(-8xy^4) = 3(-8)(x^2)(x)(y)(y^4)=-24x^3y^5
2006-10-25 09:48:54 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I'll take a guess and say that you want to eliminate negative exponents, even though you didn't specify. Remember that exponents are added when multiplied, and subtracted when divided.
x^6/x^3 = x^3
8x^-2y^5z^-3 = 8y^5/(x^2z^3) even though there's nothing wrong with the original expression
(3x^2y)(-8xy^4) = -24x^3y^5
2006-10-25 09:06:18 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
x^(6-3)=x^3
8/x^2 *y^5/z^3
=8y^5/x^2z^3
3*-8*x^(2+1)y^(1+4)
=-24x^3y^5
2006-10-25 09:04:49 · answer #3 · answered by raj 7 · 0⤊ 0⤋
E=MC2
2006-10-25 09:03:30 · answer #4 · answered by Barrett G 6 · 0⤊ 0⤋