Suppose that the temperature outside is dropping at a
constant rate. At noon, the temperature is 70_F and it drops to 58_F at 5:00 P.M.
How much did the temperature change each hour?
2006-10-25 08:58:57 · 7 answers · asked by Ryan A 1 in Education & Reference ➔ Homework Help
Well sure, (70-58) / 5 since it's 5 hours from noon till 5 pm. Then you have a change of minus 2.4 per hour, since the temperature is dropping.
2006-10-25 09:03:21 · answer #1 · answered by _______-------_______ 3 · 0⤊ 0⤋
Well first figure out how much time has gone past. Five hours have gone past.
Next figure out how much the temperature has dropped. So 70-58=12. So we know that total the temperature 12 degrees.
Than you divide 12 by 5 to split the time up evenly between the hours because you said it is dropping at a constant rate. So 12/5=2.4. So we know that the temperature has dropped 2.4 degrees each hour.
2006-10-25 16:09:11 · answer #2 · answered by butterflykisses427 5 · 0⤊ 0⤋
There is a 12 degree difference:
70 - 58= 12
Over a period of 5 hours (12:00 - 5:00)
Now divide:
12 / 5 = 2.4
The temperature dropped 2.4 degrees every hour
2006-10-25 16:03:57 · answer #3 · answered by rachellovesebay 1 · 0⤊ 0⤋
About 4 degrees or like 8.
2006-10-25 16:01:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋
12 degrees/5 hours = 2.4
2006-10-25 16:03:12 · answer #5 · answered by parrotjohn2001 7 · 0⤊ 0⤋
12 divided by 5 = 2.4 degrees/hour
2006-10-25 16:02:49 · answer #6 · answered by Me 2 · 0⤊ 0⤋
divide the difference by 5 and that will be the answer to how much the change was in one hour.
2006-10-25 16:03:17 · answer #7 · answered by saosin 3 · 0⤊ 0⤋