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Write the equation of the line that passes through point (6, 4) with a slope of 2. How??

2006-10-25 08:37:50 · 7 answers · asked by Kadie k 1 in Science & Mathematics Mathematics

7 answers

wait maybe I'll answer too. Probabaly by copying the guy above me for two points. That'll be sweet...
(two points) haha

2006-10-25 08:59:13 · answer #1 · answered by seancu2005 2 · 0 0

Use point-slope form:

y - y0 = m(x - x0)

where m is the slope, and (x0,y0) is any point on the line. In this case, m=2, x0=6 and y0=4. So you have

y - 4 = 2(x - 6)
=> y = 4 + 2x - 12
=> y = 2x - 8.

2006-10-25 15:40:00 · answer #2 · answered by James L 5 · 0 0

First, the standard form of a linear equation is y=mx+b
Now, you have points (6,4) and slope of 2
So, x=6, y=4, and m = 2
Normally we don't know y and x but know m and b, so we need to figure out b first, so substitute what we know.
4=(2)(6)+b
4=12+b
-8=b
Now, we know b, So, using y=mx+b, only fill in m and b
y=2x-8

2006-10-25 17:00:00 · answer #3 · answered by danjlil_43515 4 · 0 0

You can use the basic equation
(y-y1)=m(x-x1), giving
y-4 = 2(x-6)

If you want to solve for y, you get y = 2x-8

2006-10-25 15:41:06 · answer #4 · answered by Mr. Chemistry 2 · 0 0

y-4=2(x-6)
y-4=2x-12
2x-y-8=0

2006-10-25 15:52:42 · answer #5 · answered by raj 7 · 0 0

if y=y0 &x=x0 and slope=m then :
y-y0=m*(x-x0)
then here we have
y-4=2*(x-6)

2006-10-25 15:42:57 · answer #6 · answered by hadi m 1 · 0 0

open math book

2006-10-25 15:44:50 · answer #7 · answered by Big Rudy 3 · 0 0

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