wait maybe I'll answer too. Probabaly by copying the guy above me for two points. That'll be sweet...
(two points) haha
2006-10-25 08:59:13
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answer #1
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answered by seancu2005 2
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Use point-slope form:
y - y0 = m(x - x0)
where m is the slope, and (x0,y0) is any point on the line. In this case, m=2, x0=6 and y0=4. So you have
y - 4 = 2(x - 6)
=> y = 4 + 2x - 12
=> y = 2x - 8.
2006-10-25 15:40:00
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answer #2
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answered by James L 5
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First, the standard form of a linear equation is y=mx+b
Now, you have points (6,4) and slope of 2
So, x=6, y=4, and m = 2
Normally we don't know y and x but know m and b, so we need to figure out b first, so substitute what we know.
4=(2)(6)+b
4=12+b
-8=b
Now, we know b, So, using y=mx+b, only fill in m and b
y=2x-8
2006-10-25 17:00:00
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answer #3
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answered by danjlil_43515 4
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You can use the basic equation
(y-y1)=m(x-x1), giving
y-4 = 2(x-6)
If you want to solve for y, you get y = 2x-8
2006-10-25 15:41:06
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answer #4
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answered by Mr. Chemistry 2
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y-4=2(x-6)
y-4=2x-12
2x-y-8=0
2006-10-25 15:52:42
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answer #5
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answered by raj 7
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if y=y0 &x=x0 and slope=m then :
y-y0=m*(x-x0)
then here we have
y-4=2*(x-6)
2006-10-25 15:42:57
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answer #6
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answered by hadi m 1
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open math book
2006-10-25 15:44:50
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answer #7
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answered by Big Rudy 3
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